2x^2-3x-x^2+5=

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Solution for 2x^2-3x-x^2+5= equation:


Simplifying
2x2 + -3x + -1x2 + 5 = 0

Reorder the terms:
5 + -3x + 2x2 + -1x2 = 0

Combine like terms: 2x2 + -1x2 = 1x2
5 + -3x + 1x2 = 0

Solving
5 + -3x + 1x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-5' to each side of the equation.
5 + -3x + -5 + x2 = 0 + -5

Reorder the terms:
5 + -5 + -3x + x2 = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -3x + x2 = 0 + -5
-3x + x2 = 0 + -5

Combine like terms: 0 + -5 = -5
-3x + x2 = -5

The x term is -3x.  Take half its coefficient (-1.5).
Square it (2.25) and add it to both sides.

Add '2.25' to each side of the equation.
-3x + 2.25 + x2 = -5 + 2.25

Reorder the terms:
2.25 + -3x + x2 = -5 + 2.25

Combine like terms: -5 + 2.25 = -2.75
2.25 + -3x + x2 = -2.75

Factor a perfect square on the left side:
(x + -1.5)(x + -1.5) = -2.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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